Q:

Assume a recent sociological report states that university students drink 4.10 alcoholic drinks per week on average, with a standard deviation of 1.9101. Suppose Jason, a policy manager at a local university, decides to take a random sample of 125 university students to survey them about their drinking habits. Determine the mean and standard deviation of the sampling distribution of the sample mean alcohol consumption. Provide your answer with precision to two decimal places. Mean of sampling distribution = standard deviation of sampling distribution =

Accepted Solution

A:
Answer:4.100.17Step-by-step explanation:From the question, we know thatA recent sociological report stated that university students drink 4.10 alcoholic drinks per week on average, with a standard deviation of 1.9101.Also, we're tasked with finding the mean and standard deviation of the sampling distribution of the sample mean alcohol consumption.To find the mean of the sampling distribution, we take the sample mean of the same of that university students as a direct substitute. This then means that the mean of the sampling distribution of the sample mean alcohol consumption is 4.10 alcoholic drinks per week on average.On the other hand, the standard deviation of the sampling distribution of the sample mean alcohol consumption is taken to be the division of the standard deviation of the sample mean. Mathematically, we haveStandard Deviation, S = 1.9101 / √125Standard Deviation, S = 1.9101 / 11.18Standard Deviation, S = 0.17Therefore, the Standard Deviation is 0.17